SSC CGL MTS CHSL Reasoning Quiz ™

SSC CGL MTS CHSL Reasoning Quiz ™

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SSC CGL MTS CHSL Reasoning Quiz ™

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SSC CGL MTS CHSL Reasoning Quiz ™

Mar 31, 2026, 06:19 AM

भारत में दो नए रामसर स्थल घोषित 🌊

1. पटना बर्ड सेंचुरी,इटा(उत्तरप्रदेश)
2. छारी-ढांङ बर्ड सेंचुरी,कच्छ(गुजरात)

वर्तमान में भारत में रामसर स्थलों की संख्या 98 हो गई है।

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SSC CGL MTS CHSL Reasoning Quiz ™

Mar 31, 2026, 06:19 AM

🎓Mathematics formulas🎯

1. (α+в)²= α²+2αв+в²
2. (α+в)²= (α-в)²+4αв
3. (α-в)²= α²-2αв+в²
4. (α-в)²= (α+в)²-4αв
5. α² + в²= (α+в)² - 2αв.
6. α² + в²= (α-в)² + 2αв.
7. α²-в² =(α + в)(α - в)
8. 2(α² + в²) = (α+ в)² + (α - в)²
9. 4αв = (α + в)² -(α-в)²
10. αв =1. (α + в + ¢)² = α² + в² + ¢² + 2(αв + в¢ + ¢α)
12. (α + в)³ = α³ + 3α²в + 3αв² + в³
13. (α + в)³ = α³ + в³ + 3αв(α + в)
14. (α-в)³=α³-3α²в+3αв²-в³
15. α³ + в³ = (α + в) (α² -αв + в²)
16. α³ + в³ = (α+ в)³ -3αв(α+ в)
17. α³ -в³ = (α -в) (α² + αв + в²)
18. α³ -в³ = (α-в)³ + 3αв(α-в)
ѕιη0° =0
ѕιη30° = 1/2
ѕιη45° = 1/√2
ѕιη60° = √3/2
ѕιη90° = 1
¢σѕ ιѕ σρρσѕιтє σƒ ѕιη
тαη0° = 0
тαη30° = 1/√3
тαη45° = 1
тαη60° = √3
тαη90° = ∞
¢σт ιѕ σρρσѕιтє σƒ тαη
ѕє¢0° = 1
ѕє¢30° = 2/√3
ѕє¢45° = √2
ѕє¢60° = 2
ѕє¢90° = ∞
¢σѕє¢ ιѕ σρρσѕιтє σƒ ѕє¢
2ѕιηα¢σѕв=ѕιη(α+в)+ѕιη(α-в)
2¢σѕαѕιηв=ѕιη(α+в)-ѕιη(α-в)
2¢σѕα¢σѕв=¢σѕ(α+в)+¢σѕ(α-в)
2ѕιηαѕιηв=¢σѕ(α-в)-¢σѕ(α+в)
ѕιη(α+в)=ѕιηα ¢σѕв+ ¢σѕα ѕιηв.
» ¢σѕ(α+в)=¢σѕα ¢σѕв - ѕιηα ѕιηв.
» ѕιη(α-в)=ѕιηα¢σѕв-¢σѕαѕιηв.
» ¢σѕ(α-в)=¢σѕα¢σѕв+ѕιηαѕιηв.
» тαη(α+в)= (тαηα + тαηв)/ (1−тαηαтαηв)
» тαη(α−в)= (тαηα − тαηв) / (1+ тαηαтαηв)
» ¢σт(α+в)= (¢σтα¢σтв −1) / (¢σтα + ¢σтв)
» ¢σт(α−в)= (¢σтα¢σтв + 1) / (¢σтв− ¢σтα)
» ѕιη(α+в)=ѕιηα ¢σѕв+ ¢σѕα ѕιηв.
» ¢σѕ(α+в)=¢σѕα ¢σѕв +ѕιηα ѕιηв.
» ѕιη(α-в)=ѕιηα¢σѕв-¢σѕαѕιηв.
» ¢σѕ(α-в)=¢σѕα¢σѕв+ѕιηαѕιηв.
» тαη(α+в)= (тαηα + тαηв)/ (1−тαηαтαηв)
» тαη(α−в)= (тαηα − тαηв) / (1+ тαηαтαηв)
» ¢σт(α+в)= (¢σтα¢σтв −1) / (¢σтα + ¢σтв)
» ¢σт(α−в)= (¢σтα¢σтв + 1) / (¢σтв− ¢σтα)
α/ѕιηα = в/ѕιηв = ¢/ѕιη¢ = 2я
» α = в ¢σѕ¢ + ¢ ¢σѕв
» в = α ¢σѕ¢ + ¢ ¢σѕα
» ¢ = α ¢σѕв + в ¢σѕα
» ¢σѕα = (в² + ¢²− α²) / 2в¢
» ¢σѕв = (¢² + α²− в²) / 2¢α
» ¢σѕ¢ = (α² + в²− ¢²) / 2¢α
» Δ = αв¢/4я
» ѕιηΘ = 0 тнєη,Θ = ηΠ
» ѕιηΘ = 1 тнєη,Θ = (4η + 1)Π/2
» ѕιηΘ =−1 тнєη,Θ = (4η− 1)Π/2
» ѕιηΘ = ѕιηα тнєη,Θ = ηΠ (−1)^ηα

1. ѕιη2α = 2ѕιηα¢σѕα
2. ¢σѕ2α = ¢σѕ²α − ѕιη²α
3. ¢σѕ2α = 2¢σѕ²α − 1
4. ¢σѕ2α = 1 − ѕιη²α
5. 2ѕιη²α = 1 − ¢σѕ2α
6. 1 + ѕιη2α = (ѕιηα + ¢σѕα)²
7. 1 − ѕιη2α = (ѕιηα − ¢σѕα)²
8. тαη2α = 2тαηα / (1 − тαη²α)
9. ѕιη2α = 2тαηα / (1 + тαη²α)
10. ¢σѕ2α = (1 − тαη²α) / (1 + тαη²α)
11. 4ѕιη³α = 3ѕιηα − ѕιη3α
12. 4¢σѕ³α = 3¢σѕα + ¢σѕ3α

» ѕιη²Θ+¢σѕ²Θ=1
» ѕє¢²Θ-тαη²Θ=1
» ¢σѕє¢²Θ-¢σт²Θ=1
» ѕιηΘ=1/¢σѕє¢Θ
» ¢σѕє¢Θ=1/ѕιηΘ
» ¢σѕΘ=1/ѕє¢Θ
» ѕє¢Θ=1/¢σѕΘ
» тαηΘ=1/¢σтΘ
» ¢σтΘ=1/тαηΘ
» тαηΘ=ѕιηΘ/¢σѕΘ

SSC CGL MTS CHSL Reasoning Quiz ™

Mar 31, 2026, 06:19 AM

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SSC CGL MTS CHSL Reasoning Quiz ™

Mar 31, 2026, 06:19 AM

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SSC CGL MTS CHSL Reasoning Quiz ™

Mar 31, 2026, 06:19 AM

🏀 त्रिकोणमिति : महत्वपूर्ण सूत्र (IMP Formula) 🏀

💠 योग सूत्र 😀

🔹 Sin(A + B) = SinACosB +
CosASinB
🔺Sin(A - B) = SinACosB -
CosASinB
🔹Cos(A + B) = CosACosB -
SinASinB
🔺Cos(A - B) = CosA. CosB +
SinA. SinB

💠 अन्तर सूत्र 😀

🔹tan(A + B) = tanA + tanB/1 -
tanA.tanB
🔺tan(A - B) = tanA - tanB/1 +
tanA.tanB

💠 C - D सूत्र 😀

🔹SinC + SinD = 2Sin(C + D/2)
Cos(C - D/2)
🔺SinC - SinD = 2Cos(C + D/2)
Sin(C - D/2)
🔹CosC + CosD = 2Cos(C + D/
2) Cos(C - D/2)
🔺CosC - CosD = 2Sin(C + D/2)
Sin(D - C/2)
🔹CosC - CosD = - 2Sin(C + D/
2) Sin(C - D/2)

💠 रूपांतरण सूत्र 😀

🔹2SinA. CosB = Sin(A + B) +
Sin(A-B)
🔺2CosA. SinB = Sin(A + B) -
Sin(A - B)
🔹2CosA. CosB = Cos(A + B) +
Cos(A-B)
🔺2SinA. SinB = Cos(A - B) -
Cos(A + B)

💠 द्विक कोण सूत्र 😀

🔹Sin2A = 2SinA. CosA
🔺Cos2A = Cos²A - Sin²A =
2Cos² - 1 = 1 - 2Sin²A
🔹tan2A = 2tanA/1 - tan²A
🔺Sin2A = 2tanA/1 + tan²A
🔹Cos2A = 1 - tan²A/1 + tan²A

💠 विशिष्ट सूत्र 😀

🔹Sin(A + B) = Sin A . Cos B +
Cos A . Sin B
🔺Sin(A - B) = Sin A . Cos B −
Cos A . Sin B
🔹Cos (A + B) = Cos A . Cos B −
Sin A . Sin B
🔺Cos ( A - B ) = Cos A . Cos B
+ Sin A . Sin B

💠 त्रिक कोण सूत्र 😀

🔹Sin3A = 3SinA - 4Sin³A
🔺Cos3A = 4Cos³A - 3CosA
🔹tan3A = 3tanA - tan³A/1 - 3tan²A

💠 महत्वपूर्ण सर्वसमिकाएं 🔹

🔹Sin²θ + Cos²θ = 1
🔺Sin²θ = 1 - Cos²θ
🔹Cos²θ = 1 - Sin²θ
🔺1 + tan²θ = Sec²θ
🔹Sec²θ - tan²θ = 1
🔺tan²θ = Sec²θ - 1
🔹1 + Cot²θ = Cosec²θ
🔺Cosec²θ - Cot²θ = 1
🔹Cot²θ = Cosec²θ - 1

♦️ Post को Like share जरूर करिए..... ❤️❤️

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SSC CGL MTS CHSL Reasoning Quiz ™

Mar 31, 2026, 06:19 AM

🔰 बीजगणित के सूत्र: 🔰

🔴 (a+b)² = a²+2ab+b²

🔴 (a-b)² = a²-2ab+b²

🔴 (a-b)² = (a+b)²-4ab

🔴 (a+b)² + (a-b)² = 2(a²+b²)

🔴 (a+b)² – (a-b)² = 4ab(a+b)³ = a³+3a²b+3ab²+b³

🔴 (a+b)² – (a-b)² = a³+b³+3ab(a+b)

🔴 (a-b)³ = a³-3a²b+3ab²-b³

🔴 (a-b)³ = a³+b³+3ab(a+b)

🔴 (a+b)³ + (a-b)³ = 2(a³+3ab²)

🔴 (a+b)³ + (a-b)³ = 2a(a²+3b²)

🔴 (a+b)³ – (a-b)³ = 3a²b+2b³

🔴 (a+b)³ – (a-b)³ = 2b(3a²+b²)

🔴 a²-b² = (a-b)(a+b)

🔴 a³+b³ = (a+b)(a²-ab+b²)

🔴 a³-b³ = (a-b)(a²+ab+b²)

🔴 a³-b³ = (a-b)³ + 3ab(a-b)

🔴 (a+b+c)² = a²+b²+c²+2(ab+bc+ca)

🔴 (a+b+c)³ = a³+b³+c³+3(a+b)(b+c)(c+a)

🔴 a³+b³+c³ = (a+b+c)³ – 3(a+b)(b+c)(c+a)

🔴 (a+b+c+d)² = a²+b²+c²+d²+2(ab+ac+ad+bc+bd+cd)

🔴 a³+b³+c³-3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)।

🥰 बस 1 𝐋𝐢𝐤𝐞 ❤️ चाहिए...... ✅

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SSC CGL MTS CHSL Reasoning Quiz ™

Mar 31, 2026, 06:19 AM

🔢 वर्ग और वर्गमूल तालिका (1-30)

🔷 Squares (वर्ग):
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
6² = 36
7² = 49
8² = 64
9² = 81
10² = 100
11² = 121
12² = 144
13² = 169
14² = 196
15² = 225
16² = 256
17² = 289
18² = 324
19² = 361
20² = 400
21² = 441
22² = 484
23² = 529
24² = 576
25² = 625
26² = 676
27² = 729
28² = 784
29² = 841
30² = 900
🔶 Square Roots (वर्गमूल):
√1 = 1
√4 = 2
√9 = 3
√16 = 4
√25 = 5
√36 = 6
√49 = 7
√64 = 8
√81 = 9
√100 = 10
√121 = 11
√144 = 12
√169 = 13
√196 = 14
√225 = 15
√256 = 16
√289 = 17
√324 = 18
√361 = 19
√400 = 20
√441 = 21
√484 = 22
√529 = 23
√576 = 24
√625 = 25
√676 = 26
√729 = 27
√784 = 28
√841 = 29
√900 = 30

📍 Trick: 11² = 121, 13² = 169, 17² = 289 — ये Exams में बार-बार पूछे जाते हैं।

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